Perimeter Used.

I talk here to correct few formulas which are used for knowing perimeter.

2(l+b) is the wrong formula I say, and (l+b)/2 is the correct formula to find h so l is length, b is breath, h is height.

I write: length+breadth+height is the correct formula to find perimeter and 2(l+b) is one dimension more or extra applicable here wrong.

And I say (l+b)/2 is the height of the block as we see length and breadth so the third side is height here .

l=12 b=16

2(l+b) so 2(12+16)=56--------------1 is the wrong perimeter.

l+b+h so 12+16+x=56 according to x derived from(2 x [l+b]) so x=56-28=28 so h is 28 -----1A perimeter is 12+16+28 =56 we get wrong perimeter.

 

(l+b)/2 is h so 12+16/2=14 is h-----2A

so perimeter is l+b+h what is 12+16+14=42------------2 is the right perimeter.

 

So l+b is=28---3A (l+b)/2 is=14---4A 2(l+b) is=56---1 and l+b+h is= 42---2

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So ---1 minus ---2 is 56-42 is 14 again what is same as we get h (2A) which is from my formula (proof of my formula is correct)

 

So h we get double by incorrect formula 2(l+b) which is value 28 (1A) whereas by our formula (l+b)/2 is h I say we get h half of h-of-wrong-formula that is 14 (2A) means 28/2=14 (proof of my formula is correct).

And the proof of my formula is l+b+h perimeter is correct if the two dimension other than middle dimensions are half of/include-in middle dimension. So the third dimension is including both two dim and two sides around by my perimeter formula. As by wrong perimeter formula 2(l+b) the middle dimension includes the opposite dimension (the other corner too) so h becomes extra in extra dimension which is out side dimensions which is not their but h is present and can be counted /included by my formula.  

 

Calculations I show:

If 2(l+b) is  wrong perimeter. We take value l=12 b=16 so 2(12+16) is 56.

So for perimeter other way of wrong formula is l+b+h we see so 12+16+h=56 so h=56-28 is 28.

Now as per I say for my formula that h should be (l+b)/2 means (12+16)/2=14 what I say h should be

So for normal perimeter 12+16+14=42 is l+b+h=42

So 2(l+b) is 56 and l+b+h is 42 and (l+b)/2 is 14 so h is 14

So 2(l+b) minus (l+b+h) is 56-42=14 so this value we get same as h its something fabulous.

So we get h by removing  l+b+h from 2(l+b)which is again 14 in the above sentence I say what is h I again say like I mentioned before on this page, is the valid proof of my Theory.

So my h is correct as h by wrong formula is double means 28 instead of my h which is 14 we come to know so value of h by both formulas (right one and wrong one) shows I talk something correct as is a proof of my formula is correct.

2(l+b) is one dimension double or extra we come to know if minus (l+b+h) from it. Then we get h which is according to my formula. So  2(l+b) is 56 and l+b+h is 42 and I can say that my correct perimeter which is 42 minus h-of-wrong-formula which is 28  is also same number which is 14 which means wrong formula counts one h (means dimension and side) extra one more proof of my formula is correct.

So 2(l+b) minus (l+b+h) is 56-42=14 (l+b)/2 is also 14 so h is 14 is correct what I say.

So I mean 2(l+b) is big mess formula as formula of a cylinder perimeter it is instead of a rectangle or square block as by my formula where h=(l+b)/2 we could get some perimeter of a block (so not sliding  in a cylinder).

So this I say is only so if (l+b)/2 is h. inreal h is

Any one or two dimensions if we created more bigger we are in extra-dimension which is outside normal Time so not favourable or not balancing or not good for health. So no one  dimensions should be created bigger you can built two more as you like but the third one according to my formula it should be (l+b)/2.

So if h is if double means h is alone not counted but including one more dimension and also so one more side are counted when 2(l+b) we see is not a cylinder. Or normally  cylinder formula is 2(l+b) what people should know what is a wrong formula for a block.

So 2(l+b) minus (l+b+h) is 14 which this value 14 is same as (l+b)/2 proof of my formula is correct so h we take should be (l+b)/2 as if we take formula 2(l+b) as perimeter then h is double which is a cylinder not a rectangle on land, which doesn’t fit in Time or Dimension.