MY Formula and Angles with TIME-Value I Say.

 

 

I try to INFORM MY Formulas and 0.8125-value  has a Meaning. They can also be seen, now together.

 

3=b 4=a

 

A=adjacent, B=opposite, c=hypotenuse

 

A-squ +b-squ = c-squ

 

4-squ + 3-squ = c-squ

 

16 + 9 = 25  so c=5

 

 

 

Sin=1/cos cos=1/sin and tan=sin/cos

 

Sin=adj/hyp cos=oppo/hyp and tan opp/adj.

 

 

 

NORMALLY WE FIND SIN, COS, TAN

 

b/c =sin=4/5=0.8 ---A

 

a/c=cos=3/5=0.6---B

 

a/b=tan=3/4=0.75---C

 

NOW

 

 

 

tan=sin/cos

 

 

 

So sin=1/cos=1.67--D

 

So how cos=1/sin = 1.25---E

 

SO TAN=SIN/COS=1.336---F

 

 

 

 

 

SAME WAY 0.8 X 1.67 = 1.336 SAME AS F IS TAN WHICH A X D WE GET FROM---G

 

 

 

SO 0.6 X 1.25 =0.75 WHICHH B X E WE GET SO WE GET C----------H.

 

 

 

SAME WAY C X F =1.002----------I

 

 

 

f-squ =1.784896 so x 0.8125 =1.450228---h and c-squ=0.5625 so x 0.8125  =0.45703125---i

 

now---h x I = 0.662799515625

 

Now h/i=3.173148444444444

 

 

 

 

 

So 0.8 x 0.8125 = 0.65  -----------M

 

So 0.6 x 0.8125 = 0.4875 --N

 

So M/N=F (AZ)

 

0.75 X 0.8125 =0.609375 ----O

 

 

 

SO 1.67 X 0.8125 = 1.3569 -P

 

SO 1.25 X 0.8125 = 1.015625 --Q

 

SO P/Q=F (AZ)

 

SO 1.336 X 0.8125 = 1.0855   ---R

 

 

 

 

 

SO THE DIFFERENCE REMAINS SAME WHETHER WE multiply FOR A AND D SO FIND F, OR MULTIPLY B AND E FIND C WHICH IS TAN=SIN/COS, IN BOTH CASES THE DIFFERENCE BECOMES EQUAL FOR TAN WHETHER WE SEE M OR N we get F is ONEWAY OR SEE P OR Q we get R is other way THE OTHER WAY IF WE HAD MULTIPLIED, M AND N, OR P AND Q, BY 0.8125 IT GIVES THE SAME answer a F (AZ), so here we don't get C.

 

 

 

SO M X P=0.881985----S OR M/P =0.4790330901319183-------------(S-2)

 

SO N X Q=0.4951171875----T OR N/Q=0.48------------------(T-2)

 

SO O X R = 0.6614765625 ----U OR O/R=0.561377245508982---(U-2)

 

 

 

(THIS IS DON'T WRITE So END DIGITS ARE SAME DUE TO SIDES ARE ZERO??? C-SQU=0.75-SQU = 0.5625, AND F-SQU=1.336-SQU=1.784896 SO F-SQU X C -SQU=1.336 X 0.5625=1.004004=SAME AS G-SQU)

 

 

 

 

 

ABOUT THE TRIANGLE.

 

 

 

NOW a is 4 which is the base of the Triangle WHICH IS ADJACENT-SIDE a FORCE (means FORCE-Travelling from NOTHING).

 

Here b is 3 which is mass of the triangle WHICH IS OPPOSITE-SIDE(means SKY).

 

And c is 5 which is Hypotenuse of the tringle (which Means TIME).

 

 

 

Now Force= Mass x Time

 

So 4=3 x 5

 

= 3.75

 

 

 

Time= Force/Mass

 

So 5=4/3

 

=3.75

 

 

 

Mass=Force/Time

 

So 3=4/5

 

=3.75

 

 

 

 

 

So Mass Time and Force are equal in a Right-Angle-Triangle WE CAME TO KNOW BY MID-VALUE 3.75.

 

 

 

Now Force= Mass x Time

 

So F=3 x 5

 

= 15 is F-2B

 

SO 15/3.75=4 SO Force we get WHICH BY DIVIDING M X T BY 3.75. SO AS Mass and Time were product of multiplication we have to use division so divide 15/3.75.(AZ?)

 

 

 

Time= Force/Mass

 

So T=4/3

 

=1.33 is T-2B

 

SO 1.33 X 3.75 = 4.9875 MEANS 5 SO TIME we get WHICH by multiplying F/M WITH 3.75. SO AS TIME is the product of Division we have to use multiplication so multiply 1.33 x 3.75.(AZ)

 

 

 

Mass=Force/Time

 

So M=4/5

 

=0.8 IS M-2B

 

SO 0.8 X 3.75=3 SO MASS we get WHICH BY MULTIPLYING F/T WITH 3.75 (AZ).

 

SO AS Mass IS 3 is the product of Division we have to use multiplication so multiply 0.8 x 3.75.

 

 

 

NOW F=15 X 0.8125=12.1875----------------F-1

 

NOW T=1.33 X 0.8125=1.080625------------T-1

 

NOW M=0.8 X 0.8125=0.65-------------------M-1

 

 

 

 

 

Now F-1-A= M-1 x T-1

 

So F-1-A=0.65 X 1.080625

 

= 0.70240625 (OR F-1=12.1875 SO 12.1875 X 4 = 48.75 LIKE 12.1875/4=3.0469 )

 

So 0.70240625 x 0.8125=0.570705078125------F-1-C

 

 

 

0.570705078125 = M-1 X T-1

 

 

 

                                    T-1=0.570705078125/0.65= 0.8780078125---T-1-C

 

                                     M-1=0.570705078125/1.080625= 0.528125-M-1-C

 

                                    T-1-C X M-1-C = 0.4636978759765625

 

 

 

T-1-A= F-1/M1

 

So T-1-A=4/3

 

=18.75

 

(18.75/5=3.75)

 

 

 

M-1-A= F-1/T-1

 

So M-1-A = 11.2781954887218

 

(11.2781954887218/3=3.75)

 

 

 

(OR 18.75 X 11.2781954887218=211.4661654135338 LIKE 18.75/11.2781954887218=1.662500000000001[HERE SEE CHECK IN-TO 15 {4 X 3.75})

 

 

 

1AZ.Now f-1-A x f (so 0.70240625 x 4) (here f =4 we have to take instead of 15 [which is f-2B] AS Force is the product of multiplication which is already done so base-value or Normal-value of triangle we have to take) so we get=2.809625 so we under-root for it =1.676193604569591 which is f-squ.

 

2AZ. Now t-1-A x t-2B (so 18.75 x 1.33)=25 which is t-squ

 

3AZ. Now m-1-A x m-2B (so 11.2781954887218 x 0.8)= 9 which is m-squ

 

 

 

So Multiplying f, t, m with 0.8125 we get values that we again multiply by normal force time and mass so get value same as square of them, SOMETHING We came to Know. So 0.8125 is The MID-Value of TIME where difference between normal values and either squaring them or multiplying them with TIME-value 0.8125 is same percentage difference whether the normal value or the mid-time-multiplied value, so this value, and squaring of force time and mass has the same answer,DUE TO ALL MASS TIME AND FORCE are percentage-wise same for TIME, SO MID-TIME-VALUE USED TO MULTIPLY OR SQUARING THE VALUE HAS THE SAME ANSWER.

 

 

 

NOW MOMENTUM WE SEE-CHECK

 

 

 

 

 

So p=f x t

 

Sop=F-1 X t-1

 

So P=13.1701171875

 

 NOW P= M-1 x V

 

SO 13.1701171875 =0.65 X V

 

SO V= 20.26171875 x 0.8125 is same as f-SQU MEANS (AZ). SO HERE VELOCITY IS SAME even if we take f-1 x t-1 instead of f x t as when we see figures multiplied by 0.8125 FOR FORCE AND TIME it doesn't changes TIME SO THE VELCOITY IS SAME FOUND 16 which is square of 4 which is normal-force value(AZ)

 

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This part doesn’t shows anything.

 

M-1-SQU X T =Event-c1

 

So0.65-squ x 1.080625 =0.4565640625 (or 0.65 x 1.33=0.8645)

 

 

 

m-1 x f-1 =Event-d1

 

0.65 x 12.1875=7.921875

 

 

 

C1 x d1= 3.616843432617188 AND c1/d1=17.35106998264893 and c1-d1=7.4653109375 which multiplied by 2 is 15 gives force-2B value.

 

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So here we see 2B VALUES

 

f=15

 

t=1.33

 

m=0.8

 

 

 

 

 

m-squ x t = EVENT=0.8533

 

 

 

M X F =Event =12 SO IN 2B-VALUES TOO MULTIPLICATION OF MASS AND FORCE COMES SAME AS 12 (AZ) EVEN WHEN 2B-VALUES ARE DIFFERENT FROM NORMAL MASS AND FORCE VALUES. SO 2B-VALUES WE GOT DUE TO WE SEE FORCE FROM DIFFEREENT PERSPECTIVE AS DON'T SEE FORCE AS A VALUE 4 BUT SEE FORCE AS VALUE 15 WHICH COMES FROM MASS X TIME SHOULD BE KEPT IN MIND USED FROM 2B-VALUES.

 

 

 

p= f x t so 15 x 1.33 =19.95 or 20 SO P=20 WHICH IS SAME WITH OR WITHOUT 0.8125 MULITPLYING in the MOMENTUM equation. (AZ-DIRECT)

 

p= m x v so 20 = 0.8 x v so v= 24.9375 so v=25 which is t-squ (AZ)

 

P if multiplied by 0.8125 is normal-f-square =16 we get (AZ)

 

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4=f, 3=m , 5=t

 

 

 

p= f x t

 

p=20 (twenty is Momentum in NOTHING)

 

 

 

p=m x v

 

20=3 x v

 

v=6.67 (VELOCITY ON EARTH)

 

 

 

 

 

M x f =Event--------------1-E

 

3 x 4

 

=12 AS MASS X FORCE IS NORMAL EVENT I SAY.

 

 

 

Here 80/12 is also =6.67 which is from f-squ x time (16 x 5 = 80) (AZ) so this value divide by weight we do 6.67/(1/3) so 6.67 x 3 = 20.01 is using-time value SAME AS MOMENTUM (AZ)

 

 

 

 

 

m-squ x t = Event--------2-E

 

3 x 3 x 5 =45 AS VALUE 45 IS EVENT AFTER MOMENTUM MEANS SOME FORCE OR VELOCITY IS INCLUDED WITH MOMENTUM.

 

 in this above two event formulas if we divide BY EACHOTHER which is 45/12 we get mid-value of mass force and time as they are just event different which is 3.75 (AZ) as we use Triangle From Dimensions and live, even when Dimensions are in squares(AZ)

 

 

 

t-squ x m =e?---------3-E

 

25 x 3 =75=e? WE CHECK.

 

75/45=1.6667 WHICH IS SIN VALUE MEANS ADJ/HYP=4/5 (AZ)

 

NOW 75/4 MEANS EVENT DIVIDE BY ADJ-SIDE OR FORCE, IS 18.75 same as T-1-A (AZ)

 

NOW 75/5 MEANS  EVENT DIVIDE BY HPY OR TIME, IS 15 SAME AS F-2-B(AZ)

 

 

 

 

 

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3.75 x 4 = 15 SO WE DON'T NEED TO MULTIPLY BY 0.8125 FOR FORCE. FORCE IS BEFORE TIME AND MASS SO TWICE MULTIPLCATION IS NOT REQUIRED, AS FORCE IS THE CENTER REQUIREMENT THING TO ACT SO FORCE (4) SHOULDN'T BE MULTIPLIED BY 0.8125.

 

AND FORCE IS NOT IN TIME AS WE LIVE IN OPPOSITE TIME SO MASS IS IN OPPOSITE-TIME SO FORCE TILL THAT COMES IN TO EVENT IS NOT IN TIME SO DOESN'T REQUIRE TO BE MULTIPLIED BY 0.8125. SO FORCE DUE TO NOT CHANGED BY MASS AND TIME JUST REQUIRES TO BE MULTIPLIED BY FORCE-TRAVELLING-SPOT OR BY TIME-CENTER which is 3.25 here (AZ) in a triangle.

 

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PEOPLE TALK TO ME IF I AM WRONG, can't work single-handedly so co-operate and e-mail me for discussions still meeting in-person I Prefer.

Where ever I Write AZ IN bracket is a discovery. OR Not People seecheck. Should let me know what ideas do you have.