Momentum Formulas CONCLUDE MY formulas.

I can explain my all formulas due to momentum formula. I TRY

 

FORCE/WEIGHT = Acceleration?? (NOW F=M X A MEANS A=F/M SO A= FORCE X WEIGHT WHAT IS TOLD BY NEWTON WHEREAS I THINK FORCE X MASS = ACCELERATION or A=F/W, so f=a/m--------B I say)

SO F= M X A IF WE SEE, then mass has changed velocity for acceleration too, it can be due to additional force APPLIED all the TIME AND NOT due to constant Force so f=m x a is wrong.

SO IF WE SEE f=a/m, as from acceleration if mass is removed at that time we can experience force which is by denied or not-counted MASS AS ALONE acceleration IS AS force alone we are finding.

SO IF WE SEE A=F/M, THEN FROM FORCE mass is removed is uniform/constant speed which if we mean to remove the weight of that mass then speed keeps increasing can be, otherwise it can't be if weight is not taken into consideration TO BE REMOVED/DISPLACED.

SO IF WE SEE ACCELERATION = FORCE/WEIGHT as with acceleration if mass also moves AS MUCH AS ITS WEIGHT (REMOVED TO EXIST) is the matter as mass WITH WEIGHT also moves THEN WE FIND acceleration.

So if we see, A=Force x Weight then it seems the formula is true but then where is Force-Travelling as Due to F X W we will just feel the opposite force HALF to our applied force, AND AHEAD MASS AND TIME TOO REQUIRES TO BE KNOWN (for force-travelling) SO there is Force-Travelling between Force and Weight so the formula f=m x a is not fully correct as then can be used in space where there is no weight just mass and time who works as force (as I say force = mass x time is force)

  

FORCE/WEIGHT = Acceleration??

(M x t) / (t/f)

(f/t) x t x (f/t)=a

f-square/t = a

 

FORCE/WEIGHT = Acceleration??

(M x t) / (t/f)

(f/t) x t x (f/t) =a

So F x m/f x t x m x t x m/f

=m-cube x 1/f x t-square or m-raise-to four

(m x t) x m/f x f/m x f x m/f

=m-square x t=a

 

FORCE/WEIGHT = Acceleration?

(Mx t) x f/t

=f/t x t x f/t

=f-square x t = ACCELERATION OR M-SQUARE X TIME IS ACCELERATION.----------------------A

FORCE/WEIGHT = Acceleration? 

(M x t)/ (t/f)

M x t x f/t

= m x f is also acceleration.

So acceleration govt calcuates is Event value.

 

p= m x v or p= f x t these both formulas my formulas conclude.

SO

p= m x v

p=(f/t) x (a/T)

p=f x a)/t-square which is also or (m x t (f x a)/(t x t) we get. So m x t x f x a so f-square x a also we get.

So f-square x a we get

a=f x f x t so we put

So f-square x t is acceleration we conclude. SAME AS -------A

 

SO

p=f x t

p= m x t) x t so mass x time-square

p=m x f/m x f/m

p=f-square/m so f-cube/t so f-square x m so f x m x t/m so f-square/m is acceleration so we put f-square x t = ACCELERATION se we get f x t so we get SAME FORMULA AGAIN OF MOMENTUM.

 

p=f x t

p=m x t x f)/m

p=f/t) x t (m x t)/m

p=f x m x t/m WE PUT M X F =A SO A X T/M SO A X F /M-SQUARE SO WE PUT M-SQUARE=A/T SO A X T/A =T SO WE PUT A=V X T SO V X T X T/(V X T) SO A/T X T X T/(A/T  SO P=A-SQUARE/T-SQUARE. SO P=V-SQUARE WE GOT.

p=m x t-square we get

So we SEE CHECK

p=f x t =V-SQUARE

= V X V = MX V

V=M

Mx f is event or=f

SO PUT V=M

V X F =EVENT.

=A/T X F

=A X M/F X F

=A/M MEANS F WE GET.

SO A= F X M WE CONCLUDE SO SAME AS------------------------B I SAY.

 

SO DUE TO A….. AND B…. I Conclude Momentum formulas which can be calculated by other ways of working on equations of momentum PUTTING IN EACHOTHER, THE formulas SEEN AT DIFFERENT PLACE ON THIS PAGE. SO MORE WAYS ANSWER COULD COME.

SO BY COMPARING MOMENTUM FORMULAS WITH MY FORMULAS WE GET RIGHT ANSWERS. THESE ANSWERS CAN SHOW MASS, FORCE, TIME, VELOCITY AND SUCH THINGS WHO ARE INREAL DIFFERENT AS EQUAL ANSWER IF COMES THEN THEY ARE SAME WITHOUT EVENT, I MEANS THEY ARE JUST EVENT DIFFERENT (otherwise equal), FOR THAT KNOW MY EVENT FORMULAS LIKE MASS X FORCE IS ONE FORMULA FOR EVENT, MASS-SQUARE X TIME IS ALSO EVENT AND SUCH MORE FORMULAS.